Integrand size = 22, antiderivative size = 448 \[ \int (d+e x)^3 \left (a+b x+c x^2\right )^{5/4} \, dx=-\frac {5 \left (b^2-4 a c\right ) (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{7392 c^5}+\frac {(2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \left (a+b x+c x^2\right )^{5/4}}{616 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{9/4}}{13 c}+\frac {e \left (1320 c^2 d^2+221 b^2 e^2-2 c e (507 b d+88 a e)+306 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{9/4}}{2574 c^3}+\frac {5 \left (b^2-4 a c\right )^{9/4} (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{14784 \sqrt {2} c^{21/4} (b+2 c x)} \]
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Time = 0.38 (sec) , antiderivative size = 448, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {756, 793, 626, 637, 226} \[ \int (d+e x)^3 \left (a+b x+c x^2\right )^{5/4} \, dx=\frac {5 \left (b^2-4 a c\right )^{9/4} \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right )^2}} \left (\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}+1\right ) (2 c d-b e) \left (-4 c e (6 a e+11 b d)+17 b^2 e^2+44 c^2 d^2\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{c x^2+b x+a}}{\sqrt [4]{b^2-4 a c}}\right ),\frac {1}{2}\right )}{14784 \sqrt {2} c^{21/4} (b+2 c x)}-\frac {5 \left (b^2-4 a c\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2} (2 c d-b e) \left (-4 c e (6 a e+11 b d)+17 b^2 e^2+44 c^2 d^2\right )}{7392 c^5}+\frac {(b+2 c x) \left (a+b x+c x^2\right )^{5/4} (2 c d-b e) \left (-4 c e (6 a e+11 b d)+17 b^2 e^2+44 c^2 d^2\right )}{616 c^4}+\frac {e \left (a+b x+c x^2\right )^{9/4} \left (-2 c e (88 a e+507 b d)+221 b^2 e^2+306 c e x (2 c d-b e)+1320 c^2 d^2\right )}{2574 c^3}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{9/4}}{13 c} \]
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Rule 226
Rule 626
Rule 637
Rule 756
Rule 793
Rubi steps \begin{align*} \text {integral}& = \frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{9/4}}{13 c}+\frac {2 \int (d+e x) \left (\frac {1}{4} \left (26 c d^2-9 b d e-8 a e^2\right )+\frac {17}{4} e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{5/4} \, dx}{13 c} \\ & = \frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{9/4}}{13 c}+\frac {e \left (1320 c^2 d^2+221 b^2 e^2-2 c e (507 b d+88 a e)+306 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{9/4}}{2574 c^3}+\frac {\left ((2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right )\right ) \int \left (a+b x+c x^2\right )^{5/4} \, dx}{88 c^3} \\ & = \frac {(2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \left (a+b x+c x^2\right )^{5/4}}{616 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{9/4}}{13 c}+\frac {e \left (1320 c^2 d^2+221 b^2 e^2-2 c e (507 b d+88 a e)+306 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{9/4}}{2574 c^3}-\frac {\left (5 \left (b^2-4 a c\right ) (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right )\right ) \int \sqrt [4]{a+b x+c x^2} \, dx}{2464 c^4} \\ & = -\frac {5 \left (b^2-4 a c\right ) (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{7392 c^5}+\frac {(2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \left (a+b x+c x^2\right )^{5/4}}{616 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{9/4}}{13 c}+\frac {e \left (1320 c^2 d^2+221 b^2 e^2-2 c e (507 b d+88 a e)+306 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{9/4}}{2574 c^3}+\frac {\left (5 \left (b^2-4 a c\right )^2 (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right )\right ) \int \frac {1}{\left (a+b x+c x^2\right )^{3/4}} \, dx}{29568 c^5} \\ & = -\frac {5 \left (b^2-4 a c\right ) (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{7392 c^5}+\frac {(2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \left (a+b x+c x^2\right )^{5/4}}{616 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{9/4}}{13 c}+\frac {e \left (1320 c^2 d^2+221 b^2 e^2-2 c e (507 b d+88 a e)+306 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{9/4}}{2574 c^3}+\frac {\left (5 \left (b^2-4 a c\right )^2 (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) \sqrt {(b+2 c x)^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {b^2-4 a c+4 c x^4}} \, dx,x,\sqrt [4]{a+b x+c x^2}\right )}{7392 c^5 (b+2 c x)} \\ & = -\frac {5 \left (b^2-4 a c\right ) (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \sqrt [4]{a+b x+c x^2}}{7392 c^5}+\frac {(2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) (b+2 c x) \left (a+b x+c x^2\right )^{5/4}}{616 c^4}+\frac {2 e (d+e x)^2 \left (a+b x+c x^2\right )^{9/4}}{13 c}+\frac {e \left (1320 c^2 d^2+221 b^2 e^2-2 c e (507 b d+88 a e)+306 c e (2 c d-b e) x\right ) \left (a+b x+c x^2\right )^{9/4}}{2574 c^3}+\frac {5 \left (b^2-4 a c\right )^{9/4} (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) \sqrt {\frac {(b+2 c x)^2}{\left (b^2-4 a c\right ) \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right )^2}} \left (1+\frac {2 \sqrt {c} \sqrt {a+b x+c x^2}}{\sqrt {b^2-4 a c}}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt [4]{a+b x+c x^2}}{\sqrt [4]{b^2-4 a c}}\right )|\frac {1}{2}\right )}{14784 \sqrt {2} c^{21/4} (b+2 c x)} \\ \end{align*}
Time = 10.78 (sec) , antiderivative size = 286, normalized size of antiderivative = 0.64 \[ \int (d+e x)^3 \left (a+b x+c x^2\right )^{5/4} \, dx=\frac {88704 c^5 e (d+e x)^2 (a+x (b+c x))^3+224 c^3 e (a+x (b+c x))^3 \left (221 b^2 e^2+12 c^2 d (110 d+51 e x)-2 c e (507 b d+88 a e+153 b e x)\right )+39 (2 c d-b e) \left (44 c^2 d^2+17 b^2 e^2-4 c e (11 b d+6 a e)\right ) \left (2 c (b+2 c x) \left (32 a^2 c+a \left (-5 b^2+44 b c x+44 c^2 x^2\right )+x \left (-5 b^3+7 b^2 c x+24 b c^2 x^2+12 c^3 x^3\right )\right )+5 \sqrt {2} \left (b^2-4 a c\right )^{5/2} \left (\frac {c (a+x (b+c x))}{-b^2+4 a c}\right )^{3/4} \operatorname {EllipticF}\left (\frac {1}{2} \arcsin \left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right ),2\right )\right )}{576576 c^6 (a+x (b+c x))^{3/4}} \]
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\[\int \left (e x +d \right )^{3} \left (c \,x^{2}+b x +a \right )^{\frac {5}{4}}d x\]
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\[ \int (d+e x)^3 \left (a+b x+c x^2\right )^{5/4} \, dx=\int { {\left (c x^{2} + b x + a\right )}^{\frac {5}{4}} {\left (e x + d\right )}^{3} \,d x } \]
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\[ \int (d+e x)^3 \left (a+b x+c x^2\right )^{5/4} \, dx=\int \left (d + e x\right )^{3} \left (a + b x + c x^{2}\right )^{\frac {5}{4}}\, dx \]
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\[ \int (d+e x)^3 \left (a+b x+c x^2\right )^{5/4} \, dx=\int { {\left (c x^{2} + b x + a\right )}^{\frac {5}{4}} {\left (e x + d\right )}^{3} \,d x } \]
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\[ \int (d+e x)^3 \left (a+b x+c x^2\right )^{5/4} \, dx=\int { {\left (c x^{2} + b x + a\right )}^{\frac {5}{4}} {\left (e x + d\right )}^{3} \,d x } \]
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Timed out. \[ \int (d+e x)^3 \left (a+b x+c x^2\right )^{5/4} \, dx=\int {\left (d+e\,x\right )}^3\,{\left (c\,x^2+b\,x+a\right )}^{5/4} \,d x \]
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